The climb along an inclined path
The climb along an inclined path

The climb along an inclined path.


Considering the schedule of available capacities and needs of horizontal flight, pay attention to the fact that the entire speed range, in addition to the maximum speed, there is a significant supply of engine power. This stock may be used to climb. Consequently, the helicopter can climb on any speed other than maximum.

Vertical climb was considered above. Consider now the climb along an inclined path in the presence of forward speed.

Such a kit as well as horizontal flight is accomplished at negative angles of attack of the rotor, r. E. The flow passes through the swept surface of the screw top.

0 angle between the path of the helicopter and climb the horizon is called the angle set.

When you climb the sloping path to the helicopter, the following powers: a rotor thrust T (cm. Note, longitudinal force of the screw H, the drag force.

For the X-axis will take the direction of flight (trajectory) for the Y axis - perpendicular to the plane of the drawing in it for the axis Z - perpendicular to the plane of the figure aimed for the drawing. The origin is placed at the center of gravity of the helicopter.

Examination conditions of equilibrium of moments about the X axis and Z is the task of the longitudinal and transverse balances have been omitted here.

The climb is characterized by a set of vertical speed - rate of climb and maximum attainable height - ceiling.

Since the rotor, blown in the plane of rotation, consumes to produce the same thrust less power than without blowing, the rate of climb and ceiling climb with forward speed is greater than the vertical rise.

That limit the height to which the helicopter can climb climb at an angle to the horizon, called dynamic ceiling.

The dynamic ceiling is 1,5-3 times the static ceiling.

For each height has the most advantageous flight speed at which the rate of climb is greatest. The higher the altitude, the greater the value of the most favorable rate.

For example, if the actual ground speed of the most advantageous 1 helicopter is, for example, 80 km1chas, then at the height of 5000 m it will be for about 100 km / h.

Naturally, the climb rate increases with a decrease in gross weight of the helicopter.

If you overload the helicopter above the norm, it would not be able to make a vertical take-off and climb, but will be able to take off after takeoff, and climb will be made on an inclined path.

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